Problema Solution
A chemist wants to make a 30-ounce solution of alcohol and water that is 48% alcohol. How much of a 30% alcohol solution should be mixed with a 60% alcohol solution?
Answer provided by our tutors
Let
x = ounces of 30% alcohol solution
y = ounces of 60% alcohol solution
x + y = 30
0.30x + 0.60y = 0.48*30
........
........
x = 12 oz
y = 18 oz
12 ounces of 30% solution should be mixed with 18 ounces of 60% alcohol solution.