Problema Solution
Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $15 and same-day tickets cost $20. For one performance, there were 45 tickets sold in all, and the total amount paid for them was $750. How many tickets of each type were sold?
Answer provided by our tutors
Let
x = the number of advance tickets sold
y = the number of same-day tickets sold
There were 45 tickets sold in all:
x + y = 45
The total amount paid for them was $750:
15x + 20y = 750
We have the following system of equations:
x + y = 45
15x + 20y = 750
........
........
x = 30 advance tickets
y = 15 same-day tickets
There were 30 advance tickets and 15 same-day tickets sold.