Problema Solution
How much of a radioactive kind of cesium will be left after 26 days if you start with 56 grams and the half-life is 13 days?
Answer provided by our tutors
The amount A of the radioactive material present at a time t is given by the model
A = A0*(1/2)^(t/h)
where A0 is the amount present initially, h is the half-life of the material.
In our case we have
A0 = 56 g
h = 13 days half-life
t = 26 days
A = 56*(1/2)^(26/13)
........
........
A = 14 g
After 26 days there will be 14 g of radioactive kind of cesium left.