Problema Solution
the perimeter of a rectangle floor is 50 ft. find the dimensions of the floor if the length is 4 times the width.
Answer provided by our tutors
Let
l = the length of the rectangle, l>0
w = the width of the rectangle, w>0
P = 50 ft the perimeter of the rectangle
The length is 4 times the width:
l = 4w
The perimeter P = 2(l + w) thus:
2(l + w) = 50
We have the following system of equations:
l = 4w
2(l + w) = 50
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l = 20 ft
w = 5 ft
The dimensions of the floor are: the length is 20 ft and the width is 5 ft.