Problema Solution
How long would it take an investment of $6000 deposited at 5% annual interest compounded monthly to double in value?
Answer provided by our tutors
P = $20,000 is the principal
A = 2*P the future value is double the investment amount
t = the time in years
m = 12 compounding periods per year since interest is compounded monthly
n = m*t = 12t compounding periods
r = 0.05 or 5% annual interest
i = r/m = 0.05/12 interest rate per month
A = P(1 + i)^n
Plug the values we have into the formula:
2P = P(1 + 0.05/12)^(12t)
(1 + 0.05/12)^(12t) = 2
12t = log(2)/log(1 + 0.05/12)
........
........
t = 13.89 years
It will take approximately 14 years to double the investment.