Problema Solution

How long would it take an investment of $6000 deposited at 5% annual interest compounded monthly to double in value?

Answer provided by our tutors

P = $20,000 is the principal


A = 2*P the future value is double the investment amount


t = the time in years


m = 12 compounding periods per year since interest is compounded monthly


n = m*t = 12t compounding periods


r = 0.05 or 5% annual interest


i = r/m = 0.05/12 interest rate per month


A = P(1 + i)^n


Plug the values we have into the formula:


2P = P(1 + 0.05/12)^(12t)


(1 + 0.05/12)^(12t) = 2


12t = log(2)/log(1 + 0.05/12)

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t = 13.89 years


It will take approximately 14 years to double the investment.