Problema Solution
How much of an 80% salt solution must be mixed with 80 gallons of 24% salt solution to obtain a solution that is 70% salt?
Answer provided by our tutors
80% salt solution: x gallons
The equation is
80%*x + 24%*80 = 70%*(x+80)
We solve it
x = 368
So 368 gallons of 80% salt solution must be mixed .