Problema Solution
How much of a 40% alcohol solution must be mixed with 50 gallons of a 17% alcohol solution to obtain a solution that is 30% alcohol?
Answer provided by our tutors
(.17)(50) + (.40)x/(50+x) = .30
8.5 + .40x = .30(50 + x) = 15 + .30x
.10x = 15-8.5 = 6.5
x=6.5/.10
x = 65 gallons