Problema Solution
a projectile is fired at an angle of 60 degrees from the ground. its range is found to be 500 meters. find its initial velocity.
Answer provided by our tutors
Range R=v^2 sin2*60 /g.
500=v^2*0.866/9.81.
0.866v^2=500*9.81.
v^2=(500*9.81)/0.866
=5663.8.
v=sqrt(5663.8).
=75.26 m/sec.