Problema Solution
A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 60% pure antifreeze. The company wants to obtain 240 gallons of a mixture that contains 20% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?
Answer provided by our tutors
Let 'x' represent the gallons of water needed (0% antifreeze) and 'y' represent the gallons of the premium antifreeze solution (60% pure antifreeze).
x + y = 240
0*x + 0.60y = 0.20*240
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click here to see the system of equations solved for x and y
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x = 160 gal
y = 80 gal
160 gallons of water and 80 gallons of premium antifreeze solution must be mixed.