Problema Solution
Write the slope-intercept equation for the line that passes through
(-55, -53) and is (a) parallel and (b) perpendicular to 11x+5y=16.
Please show all of your work.
Answer provided by our tutors
a,The line has slope = -11/5
so y=-11/5*(x+55)-53 => 11x+5y=-870
b.the slope of line = 5/11
so y=5/11*(x+55)-53 => 11y-5x=-308