Problema Solution
Given the equation (x-3)^2+(y+2)^2=9,(a) find the center and radius; (b) graph; (c) find the intercepts, if any. Please show all of your work.
Answer provided by our tutors
Given the equation (x-3)^2+(y+2)^2=9
compare with
( x -x1)^2 +(y-y1)^2=r^2
centre =( 3,-2)
radius= 3
to find x intercept put y=0 in equation
( x-3)^2= 9 - 4
(x-3)^2= 5
x= sqrt 5+3
for y intercept put x=0
(y+2)^2= 9 -9
y=-2