Problema Solution
A man throws a ball straight up in the air with an initial speed of 24 meter per second.
How long does it take for the ball to return to him?
What is the maximum height of the ball above the point where it was thrown?
Answer provided by our tutors
We assume the time is t
So we have the equation
h = vt - 0.5gt^2
That is
0 = 24t - 0.5*9.8*t^2
So
t = 4.90
So it takes 4.90 s for the ball to return to him.