Problema Solution
The expression 200 – 16t^2 models the height in feet of an object that falls from an initial height of 200 feet t seconds after being dropped. Find the height of the object after 0.75 seconds.
Answer provided by our tutors
h = 200 - 16t^2
When t = 0.75, h = 200 - 16*0.75^2 = 191
So the height of the object after 0.75 seconds is 191 fts