Find three consecutive even integers such that 6 times the sum of the first and the third is 8 less than 14 times the second.

The even integers are a-2, a, a+2

6 (a -2 + a + 2) = 14 a - 8

12 a = 14 a - 8

2a = 8

a = 4

The three consecutive numbers are 2, 4, 6.