Problema Solution
The product of two consecutive integers is 71 more than their sum find the integers
Answer provided by our tutors
let two integers be x and x+1,
according to question,
(x).(x+1)=x+(x+1)+71
=>x^2 +x=2x+72
=>x^2-x-72=0
=>x^2-9x+8x-72=0
=>x(x-9)+8(x-9)=0
=>(x+8)(x-9)=0
Hence x=9 since x=-8 is not possible.
So two integers are 9 and 10.