Problema Solution
a rectangle is 4 feet longer than it is wide. If its area is 32 square feet; find its dimensions.
Answer provided by our tutors
A = 32 = lw = x(x + 4)
32 = x(x + 4)
32 = x2 + 4x
x2 + 4x − 32 = 0
(x + 8)(x − 4) = 0
(x + 8) = 0 or (x − 4) = 0
x + 8 − 8 = 0 − 8 or x − 4 + 4 = 0 + 4
x = −8 or x = 4