Problema Solution

Find the probability that a leap year will have 53 Fridays or 53 Saturdays.

Answer provided by our tutors

Number of days in a leap year = 366

Number of days in 52 weeks = 52*7 = 364

Those extra 2 days may be

SUN MON

MON TUE

TUE WED

WED THU

THU FRI

FRI SAT

SAT SUN

P(53 FRIDAYS) =  or  P(A) = 2/7

P(53 SATURDAYS) = or P(B) =  2/7

P(AB) = 1/7

P(A or B) = P(A)+P(B)-P(AB)

P(53 FRIDAYS or 53 SATURDAYS) = 2/7+2/7-1/7 = 3/7

1/7 is the probability that a leap year selected will contain 53 fridays and 53 saturdays

Therefore 3/7 is the CORRECT annswer