Problema Solution
Find the probability that a leap year will have 53 Fridays or 53 Saturdays.
Answer provided by our tutors
Number of days in a leap year = 366
Number of days in 52 weeks = 52*7 = 364
Those extra 2 days may be
SUN MON
MON TUE
TUE WED
WED THU
THU FRI
FRI SAT
SAT SUN
P(53 FRIDAYS) = or P(A) = 2/7
P(53 SATURDAYS) = or P(B) = 2/7
P(AB) = 1/7
P(A or B) = P(A)+P(B)-P(AB)
P(53 FRIDAYS or 53 SATURDAYS) = 2/7+2/7-1/7 = 3/7
1/7 is the probability that a leap year selected will contain 53 fridays and 53 saturdays
Therefore 3/7 is the CORRECT annswer