Problema Solution
The difference of the squares of two positive numbers is 45. The square of the smaller number is four times the larger number.Find the numbers.
Answer provided by our tutors
x2 - y2 = 45
x2 = 4y
4y - y2 = 45
0 = y2 - 4y + 45
0 = (y-9)(y+5)
y = 9 or y = -5, positive so y = 9
4y = x2
4(9) = x2
36 = x2
6 = x
so the numbers are 6 and 9