Problema Solution
Suppose 2000 bacteria are present at time t=0. Then t minutes later, the number of bacteria present wil be N(t)=2000(2)^t/30.
Find the number of bacteria present at 15 and 90 minutes
Answer provided by our tutors
N(t)=4000(2)t/30(squared) bacteria after 15 min. = 4000(2)*(15/30)squared
= 8000*1/4
= 2000
after 90 min. 4000(2) * (90/30)squared
= 8000*3
=24000