Problema Solution
The perimeter of a rectangle is 52m. If the width were doubled and the length were increased by 17m, the perimeter would be 96m. What is the length of the original rectangle?
Answer provided by our tutors
2l + 2b = 52
new b = 2b , new l = l + 17
4b + 2l + 34 = 96
4b + 2l = 62
2b = 10 , b = 5
l = 21