Problema Solution
If y varies directly with x, and y=10 when x=15,
find y when x=6.
If x varies inversely as y and x=2 when y=8,
find x when y=17.
If y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4,
what is the value of x when y=6 and z=2?
Answer provided by our tutors
y = kx
10 = 15k
10/15 = k
k = 10/15
k = 2/3
y = 2/3x
y = 2/3(6)
y = 12/3
y = 4
x = k/y
2 = k/8
16 = k
k = 16
x = 16/y
x = 16/17
y = kx/z2
3 = 2k/42
3 = 2k/16
48 = 2k
24 = k
k = 24
y = 24x/z2
6 = 24x/22
6 = 24x/4
24 = 24x
1 = x
x = 1