Problema Solution
Find the dimensions of a rectangle a with the greatest area whose perimeter is 30 feet.
Answer provided by our tutors
a + b = 30 aand A = ab
A = a(30-a)
dA/da = 30 - 2a = 0
== > a = 15
hence, dimension of area is 15 by 15 feet
Find the dimensions of a rectangle a with the greatest area whose perimeter is 30 feet.
a + b = 30 aand A = ab
A = a(30-a)
dA/da = 30 - 2a = 0
== > a = 15
hence, dimension of area is 15 by 15 feet