Problema Solution
Boyle's Law, applied to the amount of gas used in a given experiment at a constant temperature, states that pV = 240 where p is pressure measured in kilopascals and V is volume measured in cubic centimeters.If a decrease in pressure of 1 kPa produces an increase in volume of 20 cm^3, what was the original pressure on the gas?
Answer provided by our tutors
p*v=240
(p-1)(v+20)=p*v
solving this two equations we get volume v=60 and p=4kpa