Problema Solution
If a ball is thrown directly upward with a velocity of 40 m/s,its height (in meters) after t seconds is given by y=40t-16t^2.What is the maximum height attained by the ball?
Answer provided by our tutors
as the equation given is y=40t-16t^2
it reaches max. pt at time 1.25 sec
so h max is 25m