Problema Solution
A radiator contains 25 quarts of a water and antifreeze solution, which is 60% antifreeze. How
much of this solution should be drained and replaced with water to obtain a solution with 40%
antifreeze?
Answer provided by our tutors
let x be =amount of pure water to be added to obtain 40% antifreeze
(100) x + 40*(25 - x) = 60*(25)
(100-40)x = (60 - 40)*25
60*x = 20*(25)
x = (20)(25))/60
x = 8.33quarts of water