Problema Solution
Find three consectutive odd intergers such that the sum of the first, two times the second, and three times the third is 70.
Answer provided by our tutors
First integer = x+2 Second integer = x+4 Third integer = x+6 Total = 70 . So, (x+2)+2(x+4)+3(x+6)=70 x+2+2x+8+3x+18=70 6x+28=70
6x=70-28
6x=42
x=7
.
Plugging the values back in:
x+2=7+2=9
x+4=7+4=11
x+6=7+6=13
.
and
9+(2)11)+3(13)=70