Problema Solution
The radiator in a car is filled with a solution of 60 per cent antifreeze and 40 per cent water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50 per cent antifreeze. If the capacity of the raditor is 4.1 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50 per cent?
Answer provided by our tutors
60% anti freeze = 2.46 lt
40 % water =1.64 lt
Increase in % of water to 50 % , then 50% = 2.05
So 2.46-2.05 =0.41 lt of coolen should be drained and replaced with pure water to
reduce the antifreeze concentration to 50
per cent