Problema Solution
A runner runs a course at a constant speed of 6 mph. One hour after the runner begins, a cyclist starts on the same course at a constant speed of 15 mph. How long after the runner starts does the cyclist overtake the runner?
Answer provided by our tutors
distance covered by runner in 1 hr =6 miles
now cyclist strts
suppose it takes time "t" to catch
distance covered by runner in time "t" = 6t
total distance required to be covered by cyclist = 6+6t
6+6t=15t
6=9t
t=6/9 hrs
=2/3 hrs=40 min