Adult American have normally distributed heights with a mean of 5.8 feet and a standard deviation of 0.2 feet.

What is the probability that a randomly chosen adult American male will

have a height between 5.6 feet and 6.0 feet?

Solution:

Z-score of x=5.6 is Z = (5.6-5.8)/0.2 = -1

Z-score of x=6.0 is Z = (6.0-5.8)/0.2 = 1

P(5.6So the probability that a randomly chosen adult American male will have a height between 5.6 feet and 6.0 feet is 0.683