Problema Solution
Two cars leave towns 450 kilometers apart at the same time and travel towards each other. 1 cars rate is 18 kilometers per hour less than the other. If they meet in 3 hours what is the rate of the slower car?
Answer provided by our tutors
Let
v = the rate of the slower car
v + 18 = the rate of the faster car
t = 3 hr the time of the travel
d = 450 km the distance between the towns
Since distance = speed*time we have:
v*t + (v + 18)*t = d
3v + 3(v + 18) = 450
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click here to see the equation solved for v
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v = 66 km/h
The rate of the slower car was 66 km per hour.