Problema Solution
Two cars leave towns 600 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?
Answer provided by our tutors
Let
v = the rate of the slower car
v + 14 = the rate of the faster car
d = 600 km the distance between the cars
t = 3 hr the time of the travel
Since Distance = Rate*Time and the cars are traveling towars eachother, we have:
vt + (v + 14)t = d
3v + (v + 14)*3 = 600
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Click here to see the step by step solving for v
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v = 93 kph
The rate of the slower car is 93 kph.