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Math 4650 Midterm Exam 1 Solutions

1. Use Horner's scheme to evaluate where  p(x) = x3 - 2x2 + 5.

Solution : Horner's scheme becomes in this case as follows (note that you must insert a zero entry
for the missing x- term ):

From the bottom row, we read off

2. The function g(x) = ex - 2 has a fixed point near x = 1.146. Determine if the iteration
will converge or diverge if is located near this point.

Solution : Since near the fixed point x ≈ 1.146 This implies that the fixed
point iteration diverges near to it.

3. The figure to the right displays the function
near the origin. Its only root is
located
at x = 0.

a. Determine the value of the constant c
with the property that Newton 's method
will converge to the root if |x0| < c and
diverge away from it if |x0| > c.

b. When Newton's method converges for
this function, determine weather the
convergence rate will be linear , or not?

Solution: Differentiating gives Newton's iteration
therefore takes the form

(1)

a. Looking at the illustration of , it is clear that the break point between
convergence and divergence will occur when (causing an oscillation in the
iterates that will remain of equal magnitude forever). In this case, the relation (1) gives
i.e. and c = 2.

b. Linear convergence requires that   with . Since the present root is
located at x = 0, we have (in view of (1)) This limit is equal to
one, violating the requirement Hence, the convergence is NOT linear.

4. Multiple choice - for each question, mark below by a cross either True or False (i.e. not always
correct). You do not need to give any explanations for your answers to this problem.

  True False
a. If the error n in an iterative process satisfies
then the order of convergence is .
b. The bisection method for solving f (x) = 0 requires f(x) to be
differentiable (i.e. requires that f'(x) exists).
c. Müller's method is quadratically convergent .
d. Aitken's method will turn a linearly convergent sequence into a
quadratically convergent one.
e. Steffensen's method, when applied to the fixed point scheme in Problem
2 above, will produce quadratic convergence.
f. Horner's scheme is also known as synthetic division .
g. In the case of a simple root , Laguerre's method converges with
order four.
h. The matrix is singular.
i. A triangular matrix can always be inverted.
j. The vector norms ||x||1 and ||x||2 are 'equivalent'.







 

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