Problema Solution
A basketball team sells tickets that costs $10, $20, or for VIP seats $30. The team has sold 3450 tickets overall. It has sold 190 more $20 tickets than $10 tickets. The total sales are $67,310. How many tickets of each kind have been sold
Answer provided by our tutors
Let
x = the number of $10 tickets sold
y = the number of $20 tickets sold
z = the number of $30 VIP tickets sold
The team has sold 3450 tickets overall means:
x + y + z = 3450
It sold 190 more $20 tickets than $10 tickets means:
y = 190 + x
The total sales are $67,310 means:
10x + 20y + 30z = 67310 divide both sides by 10
x + 2y + 3z = 6731
Now we have the following system of equations:
x + y + z = 3450
y = 190 + x
x + 2y + 3z = 6731
........
Click here to see the step by step solution for x , y and z
........
x = 1,143 $10 tickets
y = 1,333 $20 tickets
z = 974 VIP tickets
There were 1,143 $10 tickets, 1,333 $20 tickets and 974 VIP tickets sold.