Problema Solution
how many liters of a 40% alcohol solution must be mixed with 40 liters of a 90% solution to get a 50% solution
Answer provided by our tutors
Let amount of 40% alcohol=x liter
so,
x*0.40+40*0.90=(x+40)(0.50)
.04x+36=0.50x+20
0.46x=16
x=34.78
Amount of 40% alcohol needed=34.78 liters.