Problema Solution
how many gallons of 90% antifreeze must you mix with 100 gallons of 25% antifreeze to get 80%
Answer provided by our tutors
We can write:
.90x+.25(100)=.80(x+100)
Where '.90', '.25', and '.80' are the fraction values of 90%, 25%, and 80% and 'x', '100', and 'x+100' are the amounts of each of these percentages that is needed, respectively.
Using Algebrator to solve for 'x', we get:
x=550 gallons
this is the amount of 90% antifreeze needed.