Problema Solution
The first aircraft has 59 more seats that the second aircraft. The third aircraft has 49 fewer seats than the second aircraft. If their total number of seats is 427, find the number of seats for each aircraft?
Answer provided by our tutors
let
x = the number of seats in the first aircraft
y = the number of seats in the second aircraft
z = the number of seats in the third aircraft
the first aircraft has 59 more seats that the second aircraft
x = 59 + y
the third aircraft has 49 fewer seats than the second aircraft
z = y - 49
total number of seats is 427
x + y + z = 427
by solving the system of equations
x = 59 + y
z = y - 49
x + y + z = 427
we find
x = 198 seats
y = 139 seats
z = 90 seats
click here to see the step by step solution of the system of equations
the first aircraft has 198 seats.
the second aircraft has 139 seats.
the third aircraft has 90 seats.