Problema Solution
explain how to solve a quadratic equation using the quadratic formula. Demonstrate the process with your own example. I am so confused with this.
Please provide a problem for me to try.
Answer provided by our tutors
Quadratic Formula is
... .... ._______
-b ± √(b² - 4ac)
----------------------- = x
.......2a
ax² + bx + c = 0,
To solve a quadratic equation like ax² + bx + c = 0, substitute the values into the formula and solve.
Here, first we need to identify the equation which is exactly matching with the formula format
We have here x is variable; we can take y or z as well.
Example:
6x² - 5x - 4 = 0,
Now match this with ax² + bx + c = 0,
... .... ._______
-b ± √(b² - 4ac)
----------------------- = x
.......2a
For 6x² - 5x - 4 = 0, a = 6, b = -5, and c = -4.
... .... . _____________
-(-5) ± √((-5)² - 4(6)(-4))
---------------------------------- = x
.......2(6)
.... . ________
5 ± √25 + 144
----------------------- = x
....... 12
.... . ___
5 ± √169
------------- = x
. . 12
5 ± 13
---------- = x
. 12
(5 + 13)/12
= 18/12
= 3/2 <==ANSWER
Also for the other part
(5 - 13)/12
= -8/12
= -2/3 <==ANSWER