# Products and Quotients of Ration

# Products and Quotients of Rational Functions

Section 7.4 Products and Quotients of Rational Functions 661

In this section we deal with products and quotients of
rational expressions. Before we

begin, we’ll need to establish some fundamental definitions and technique. We
begin

with the definition of the product of two rational numbers.

Definition 1. Let a/b and c/d be rational
numbers. The product of theserational numbers is defined by or more compactly |

The definition simply states that you should multiply the
numerators of each rational

number to obtain the numerator of the product , and you also multiply the

denominators of each rational number to obtain the denominator of the product.
For

example,

Of course, you should also check to make sure your final
answer is reduced to lowest

terms.

Let’s look at an example.

** Example 3. **Simplify the product of
rational numbers

First, multiply numerators and denominators together as follows.

However, the answer is not reduced to lowest terms . We can
express the numerator as

a product of primes.

210 = 21 · 10 = 3 · 7 · 2 · 5 = 2 · 3 · 5 · 7

It’s not necessary to arrange the factors in ascending
order, but every little bit helps.

The denominator can also be expressed as a product of primes.

2310 = 10 · 231 = 2 · 5 · 7 · 33 = 2 · 3 · 5 · 7 · 11

We can now cancel common factors .

662 Chapter 7 Rational Functions

However, this approach is not the most efficient way to proceed, as multiplying
numerators

and denominators allows the products to grow to larger numbers, as in 210/2310.

It is then a little bit harder to prime factor the larger numbers.

A better approach is to factor the smaller numerators and denominators
immediately,

as follows.

We could now multiply numerators and denominators, then
cancel common factors,

which would match identically the last computation in **equation (5).**

However, we can also employ the following cancellation rule.

Cancellation Rule. When working with the
product of two or more rationalexpressions, factor all numerators and denominators, then cancel. The cancellation rule is simple: cancel a factor “on the top” for an identical factor “on the bottom.” Speaking more technically, cancel any factor in any numerator for an identical factor in any denominator. |

Thus, we can finish our computation by canceling common
factors, canceling “something

on the top for something on the bottom.”

Note that we canceled a 2, 3, 5, and a 7 “on the top” for
a 2, 3, 5, and 7 “on the

bottom.”

Thus, we have two choices when multiplying rational expressions:

• Multiply numerators and denominators, factor, then cancel.

• Factor numerators and denominators, cancel, then multiply numerators and denom-

inators.

It is the latter approach that we will use in this section. Let’s look at
another

example.

Section 7.4 Products and Quotients of Rational Functions 663

**Example 6.** Simplify the expression

State restrictions.

Use the ac-test to factor each numerator and denominator. Then cancel as shown.

The first fraction’s denominator has factors x − 3 and x +
5. Hence, x = 3 or x = −5

will make this denominator zero. Therefore, the 3 and −5 are restrictions.

The second fraction’s denominator has factors x + 2 and x − 4. Hence, x = −2 or

x = 4 will make this denominator zero. Therefore, −2 and 4 are restrictions.

Therefore, for all values of x, except the restrictions −5, −2, 3, and 4, the
left side

of

is identical to its right side.

It’s possible to use your graphing calculator to check your results. First, load
the

left- and right-hand sides of **equation (8)** into the calculator’s into Y1
and Y2 in your

graphing calculator ’s Y= menu, as shown in **Figure 1**(a). Press 2nd TBLSET
and set

TblStart = −6 and ΔTbl = 1, as shown in **Figure 1**(b). Make sure that AUTO
is

highlighted and selected with the ENTER key on both the independent and
dependent

variables. Press 2nd TABLE to produce the tabular display in **Figure 1**(c).

Figure 1. Using the table features of the graphing
calculator to check the result in

**equation (8).**

Remember that the left- and right-hand sides of equation (8) are loaded in Y1
and

Y2, respectively.

664 Chapter 7 Rational Functions

• In **Figure 1**(c), note the ERR (error) message at
the restricted values of x = −5

and x = −2. However, other than at these two restrictions, the functions Y1 and

Y2 agree at all other values of x in **Figure 1**(c).

• Use the down arrow to scroll down in the table to produce the tabular results
shown

in **Figure 1**(d). Note the ERR (error) message at the restricted values of
x = 3 and

x = 4. However, other than at these two restrictions, the functions Y1 and Y2
agree

at all other values of x in **Figure 1**(d).

• If you scroll up or down in the table, you’ll find that the functions Y1 and
Y2 agree

at all values of x other than the restricted values −5, −2, 3, and 4.

Let’s look at another example.

Example 9. Simplify

State any restrictions.

The first numerator can be factored using the difference of two squares pattern .

The second denominator is a perfect square trinomial and
can be factored as the square

of a binomial .

You will want to remove the greatest common factor from
the first denominator and

second numerator.

and

Thus,

We’ll need to execute a sign change or two to create
common factors in the numerators

and denominators. So, in both the first and second numerator, factor a −1 from
the

factor 3 − x to obtain 3 − x = −1(x − 3). Because the order of factors in a
product

doesn’t matter, we’ll slide the −1 to the front in each case.

We can now cancel common factors.

Section 7.4 Products and Quotients of Rational Functions 665

A few things to notice:

• The factors 3 + x and x + 3 are identical, so they may be cancelled, one on
the top

for one on the bottom.

• Two factors of x − 3 on the top are cancelled for (x − 3)^{2} (which is
equivalent to

(x − 3)(x − 3)) on the bottom.

• An x on top cancels an x on the bottom.

• We’re left with two minus signs (two −1’s) and a 2. So the solution is a
positive 2.

Finally, the first denominator has factors x and x + 3, so x = 0 and x = −3 are

restrictions (they make this denominator equal to zero). The second denominator
has

two factors of x − 3, so x = 3 is an additional restriction .

Hence, for all values of x, except the restricted values −3, 0, and 3, the
left-hand

side of

is identical to the right-hand side. Again, this claim is
easily tested on the graphing

calculator which is evidenced in the sequence of screen captures in **Figure 2**.

Figure 2. Using the table features of the graphing
calculator to check the result in

**equation (11).
**

An alternate approach to the problem in

**equation (10)**is to note differing orders

in the numerators and denominators (descending, ascending powers of x) and anticipate

the need for a sign change. That is, make the sign change before you factor.

For example, negate (multiply by −1) both numerator and fraction bar of the first

fraction to obtain

According to our sign change rule, negating any two parts
of a fraction leaves the

fraction unchanged.

666 Chapter 7 Rational Functions

If we perform a similar sign change on the second fraction
(negate numerator and

fraction bar), then we can factor and cancel common factors.

**Division of Rational Expressions**

A simple definition will change a problem involving division of two rational
expressions

into one involving multiplication of two rational expressions. Then there’s
nothing left

to explain, for we already know how to multiply two rational expressions.

So, let’s motivate our definition of division. Suppose we ask the question, how
many

halves are in a whole? The answer is easy, as two halves make a whole. Thus,
when

we divide 1 by 1/2, we should get 2. There are two halves in one whole.

Let’s raise the stakes a bit and ask how many halves are in six? To make the

problem more precise, imagine you’ve ordered 6 pizzas and you cut each in half.
How

many halves do you have? Again, this is easy when you think about the problem in

this manner, the answer is 12. Thus,

(how many halves are in six) is identical to

6 · 2,

which, of course, is 12. Hopefully, thanks to this opening
motivation, the following

definition will not seem too strange.

Definition 12. To perform the division
invert the second fraction and multiply, as in |

Thus, if we want to know how many halves are in 12, we
change the division into

multiplication (“invert and multiply”).

Section 7.4 Products and Quotients of Rational Functions 667

This makes sense, as there are 24 “halves” in 12. Let’s
look at a harder example.

** Example 13**.
Simplify

Invert the second fraction and multiply. After that, all
we need to do is factor

numerators and denominators, then cancel common factors.

An interesting way to check this result on your calculator
is shown in the sequence of

screens in **Figure 3**.

Figure 3. Using the calculator to check division of
fractions.

After entering the original problem in your calculator, press ENTER, then press
the MATH

button, then select 1:I Frac from the menu and press ENTER. The result is shown
in

**Figure 3**(c), which agrees with our calculation above.

Let’s look at another example.

**Example 15**.
Simplify

State the restrictions.

Note the order of the first numerator differs from the other numerators and
denominators,

so we “anticipate” the need for a sign change, negating the numerator and

fraction bar of the first fraction. We also invert the second fraction and
change the

division to multiplication (“invert and multiply”).

The numerator in the first fraction in **equation (17)**
is a quadratic trinomial, with

ac = (2)(−9) = −18. The integer pair 3 and −6 has product −18 and sum −3. Hence,

668 Chapter 7 Rational Functions

The denominator of the first fraction in **equation (17)
**easily factors using the difference

of two squares pattern.

The numerator of the second fraction in **equation (17)**
is a quadratic trinomial, with

ac = (2)(−12) = −24. The integer pair −3 and 8 have product −24 and sum 5.
Hence,

To factor the denominator of the last fraction in **
equation (17),** first pull the greatest

common factor (in this case x), then complete the factorization using the
difference of

two squares pattern.

We can now replace each numerator and denominator in **
equation (17)** with its factorization,

then cancel common factors.

The last denominator has factors x and x − 4, so x = 0 and
x = 4 are restrictions.

In the body of our work, the first fraction’s denominator has factors x + 4 and
x − 4.

We’ve seen the factor x − 4 already, so only the factor x + 4 adds a new
restriction,

x = −4. Again, in the body of our work, the second fraction’s denominator has
factors

x, 2x + 3, and 2x − 3, so we have added restrictions x = 0, x = −3/2, and x =
3/2.

There’s one bit of trickery here that can easily be overlooked. In the body of
our

work, the second fraction’s numerator was originally a denominator before we
inverted

the fraction. So, we must consider what makes this numerator zero as well .
Fortunately,

the factors in this numerator are x + 4 and 2x − 3 and we’ve already considered
the

restrictions produced by these factors.

Hence, for all values of x, except the restricted values −4, −3/2, 0, 3/2, and
4, the

left-hand side of

Section 7.4 Products and Quotients of Rational Functions
669

is identical to the right-hand side.

Again, this claim is easily checked by using a graphing calculator, as is
partially

evidenced (you’ll have to scroll downward to see the last restriction come into
view) in

the sequence of screen captures in **Figure 4**.

Figure 4. Using the table feature of the calculator to
check the result in **equation (18)**.

**Alternative Notation.** Note that the fractional expression a/b means “a
divided

by b,” so we can use this equivalent notation for a ÷ b. For example, the
expression

is equivalent to the expression

Let’s look at an example of this notation in use.

**Example 21.**
Given that

and

simplify both f(x)g(x) and f(x)/g(x).

First, the multiplication. There is no possible cancellation, so we simply
multiply

numerators and denominators.

This result is valid for all values of x except −3.

On the other hand,

670 Chapter 7 Rational Functions

When we “invert and multiply,” then cancel, we obtain

This result is valid for all values of x except −3 and 0.

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