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# MATRIX OPERATIONS

Summary of article :
What is an operation?
Multiplication of a Matrix by a scalar.
Subtraction of two matrices : two ways to do it.
Combinations of Addition, Subtraction, Scalar Multiplication.
Matrix Multiplication

An operation is a way that we combine two elements.

The basic operations are:

Subtraction (-)
Multiplication ( * )
Division ( ÷ )

Here are some examples of combining elements and the operations used :

Combining elements that are rational numbers ( fractions ) using the operation of addition. Combining elements that are second degree binomials using the operation of
multiplication. Combining elements that are integers using the operation of division.

−35 ÷ 7

This FAQ will review the definitions of addition, scalar multiplication, subtraction, and
the multiplication of matrices. Division is undefined for matrices, but there is a separate
related concept, Inverse Matrices, that is similar to division and is found among the other
FAQ topics listed on the Online Math Center .

To add two matrices, their orders (the number of rows and columns in both matrices)
must be the same.

Add the corresponding row-column elements from each Matrix to produce a new element
in the same row-column location.

Example 1: Both matrices are order 2 x 2 Example 2: Both matrices are order 3 x 5 MULTIPLICATION of a MATRIX by a scalar

A scalar is simply a number . To multiply a Matrix by a scalar, distribute the scalar to all
elements in the Matrix and multiply.

Example 1: Multiply Matrix A by the scalar 3: Example 2: Multiply Matrix B by the scalar : SUBTRACTION of TWO MATRICES

To subtract two matrices, their orders (the number of rows and columns in both matrices)
must be the same.

The easy way…

To subtract Matrix A and B, simply subtract corresponding row-column elements.
Don’t forget to change signs of elements in Matrix B

Example 1: Subtract Matrix B from Matrix A. Both are order 2 x 2. Example 2: Subtract Matrix B from Matrix A. Both are order 1 x 4. Example 3: Subtract D from C Matrix C is a 3 x 3 order Matrix. Matrix D is a 3 x 1 order Matrix.
Since the order of the two matrices is different , they can NOT be subtracted.

Now the mathematics behind the scenes…

The negative sign in front of the second Matrix is actually the scalar “ −1”.
Distribute the scalar “ −1” to all elements in the second Matrix.
Add the corresponding row-column elements from each Matrix to produce a new element
in the same row-column location.

Example: Subtract B from A COMBINATIONS of ADDITION, SUBTRACTION, and Scalar
MULTIPLICATION.

The order of operations requires multiplication be done before addition or subtraction, so
first multiply the elements inside a Matrix by the scalar in front of it. Add and/or subtract
afterwards.

Example: Find 3A− 5B MULTIPLICATION of TWO MATRICES

Two matrices A and B can be multiplied if the number of columns in A is the same as
the number of rows in B. The new Matrix will have the same number of rows as A and
the same number of columns as B.

Example, find A* B Matrix A is 2 x 3 (2 rows, 3 columns). Matrix B is a 3 x 3 (3 rows, 3 columns) Matrix.
The columns in A equal the rows in B, so we can multiply A*B producing a 2 x 3 Matrix.
However, the columns in B do not equal the rows in A, so we can not multiply B*A.

Steps in multiplying two matrices

1. Determine if the two matrices can be multiplied, i.e. the number of columns in A
equals the number of rows in B.
If the order of A is (m x n) and the order of B is (n x p), the new Matrix will be of
order (m x p).
2. Set up the new, blank (m x p) Matrix.
3. Pick a row-column location of an element in the new Matrix, e.g. the element in
row 1 column 1 of the new Matrix.
4. Multiply the first element from the identified row in A by the first element in the
identified column of B. Multiply the second element from the identified row of A
by the second element in the identified column of B. Continue across the row of A
and down the column of B. Then add all of the results. Place the answer in the
new Matrix at the row-column location identified.
5. Continue until all row-column locations of the new Matrix are filled.

Example: Matrix A has 2 rows and 2 columns; Matrix B has 2 rows and 2 columns. The number of
columns in A equals the number of rows in B, so the two matrices can be multiplied.
The (2 x 2) times (2 x 2) will produce a new (2 x 2) Matrix. Set up the new, blank 2 x 2
Matrix. The question mark has been placed in the first row, first column location of the new
Matrix. So multiply the first element in row 1 of Matrix A by the first element in column
1 of Matrix B. Then multiply the second element in row 1 of Matrix A by the second
element in column 1 of Matrix B. Multplying row 1 of A by column 1 of B: We have gone across row 1 in Matrix A and down column 1 in Matrix B, so we can add
the results and place the answer in row 1-column 1 of the new Matrix New Matrix: row 1, column 1: Now let’s find the element for row 1, column 2:  Multplying row 1 of A by column 2 of B: So row 1, column 2 of the new Matrix is the element 33: For row 2, column 1 multiply row 2 of Matrix A and column 1 of Matrix B.
For row 2, column 2 multiply row 2 of Matrix A and column 2 of matrix B: Hence: Example: Find A * B A is order (1 x 3) and B is order (3 x 1), so the new matrix will be order (1 x 1): [?]

There is only one element in the new matrix: the row 1, column 1 element.
Multiply row 1 elements of Matrix A by column 1 elements of Matrix B and add the
result. Example: Find A * B A is order (2 x 3) and B is order (3 x 2), so the new matrix will be order (2 x 2): Row 1, Column 1: (1)(5) + (0)(1) + (4)(7) = 5 + 0 + 28 = 33

Row 1, Column 2: (1)(0) + (0)(6) + (4)(−2) = 0 + 0 −8 = −8

Row 2, Column 1: (−1)(5) + (2)(1) + (3)(7) = −5 + 2 + 21 =18

Row 2, Column 2: (−1)(0) + (2)(6) + (3)(−2) = 0 +12 − 6 = 6 Prev Next